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1201413973 is a prime number
BaseRepresentation
bin100011110011100…
…0001111101010101
310002201200011010211
41013213001331111
54430030221343
6315114245421
741525564434
oct10747017525
93081604124
101201413973
11567192111
12296426871
13161b9ac56
14b57bb11b
157071979d
hex479c1f55

1201413973 has 2 divisors, whose sum is σ = 1201413974. Its totient is φ = 1201413972.

The previous prime is 1201413949. The next prime is 1201413989. The reversal of 1201413973 is 3793141021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 821280964 + 380133009 = 28658^2 + 19497^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201413973 - 29 = 1201413461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201413673) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600706986 + 600706987.

It is an arithmetic number, because the mean of its divisors is an integer number (600706987).

Almost surely, 21201413973 is an apocalyptic number.

It is an amenable number.

1201413973 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201413973 is an equidigital number, since it uses as much as digits as its factorization.

1201413973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4536, while the sum is 31.

The square root of 1201413973 is about 34661.4190852019. The cubic root of 1201413973 is about 1063.0757860565.

Adding to 1201413973 its reverse (3793141021), we get a palindrome (4994554994).

The spelling of 1201413973 in words is "one billion, two hundred one million, four hundred thirteen thousand, nine hundred seventy-three".