1201432019 has 2 divisors, whose sum is σ = 1201432020. Its totient is φ = 1201432018.

The previous prime is 1201432003. The next prime is 1201432021. The reversal of 1201432019 is 9102341021.

It is a strong prime.

It is an emirp because it is prime and its reverse (9102341021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1201432019 - 2⁴ = 1201432003 is a prime.

It is a super-2 number, since 2×1201432019² = 2886877792556832722, which contains 22 as substring.

Together with 1201432021, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201431985 and 1201432003.

It is not a weakly prime, because it can be changed into another prime (1201432919) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600716009 + 600716010.

It is an arithmetic number, because the mean of its divisors is an integer number (600716010).

Almost surely, 2^1201432019 is an apocalyptic number.

1201432019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201432019 is an equidigital number, since it uses as much as digits as its factorization.

1201432019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

The square root of 1201432019 is about 34661.6794024756. The cubic root of 1201432019 is about 1063.0811087208.

The spelling of 1201432019 in words is "one billion, two hundred one million, four hundred thirty-two thousand, nineteen".