Base | Representation |
---|---|
bin | 1010111011010101010000… |
… | …0110001000110011101001 |
3 | 1120112120100120222201022102 |
4 | 2232311110012020303221 |
5 | 3033321030203000433 |
6 | 41315204401503145 |
7 | 2350004612406323 |
oct | 256652406106351 |
9 | 46476316881272 |
10 | 12014434421993 |
11 | 3912325019783 |
12 | 1420589941ab5 |
13 | 691c580029a3 |
14 | 2d7704a5a613 |
15 | 15c7ca2664e8 |
hex | aed54188ce9 |
12014434421993 has 2 divisors, whose sum is σ = 12014434421994. Its totient is φ = 12014434421992.
The previous prime is 12014434421971. The next prime is 12014434422059. The reversal of 12014434421993 is 39912443441021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11050126133929 + 964308288064 = 3324173^2 + 981992^2 .
It is a cyclic number.
It is not a de Polignac number, because 12014434421993 - 26 = 12014434421929 is a prime.
It is not a weakly prime, because it can be changed into another prime (12014434421963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007217210996 + 6007217210997.
It is an arithmetic number, because the mean of its divisors is an integer number (6007217210997).
Almost surely, 212014434421993 is an apocalyptic number.
It is an amenable number.
12014434421993 is a deficient number, since it is larger than the sum of its proper divisors (1).
12014434421993 is an equidigital number, since it uses as much as digits as its factorization.
12014434421993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 746496, while the sum is 47.
The spelling of 12014434421993 in words is "twelve trillion, fourteen billion, four hundred thirty-four million, four hundred twenty-one thousand, nine hundred ninety-three".
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