Base | Representation |
---|---|
bin | 100011110011100… |
… | …1001010100100101 |
3 | 10002201201200111212 |
4 | 1013213021110211 |
5 | 4430032203013 |
6 | 315115041205 |
7 | 41526051401 |
oct | 10747112445 |
9 | 3081650455 |
10 | 1201444133 |
11 | 56720283a |
12 | 296440205 |
13 | 161bab8b6 |
14 | b57c8101 |
15 | 707236a8 |
hex | 479c9525 |
1201444133 has 2 divisors, whose sum is σ = 1201444134. Its totient is φ = 1201444132.
The previous prime is 1201444117. The next prime is 1201444141. The reversal of 1201444133 is 3314441021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 830419489 + 371024644 = 28817^2 + 19262^2 .
It is an emirp because it is prime and its reverse (3314441021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1201444133 - 24 = 1201444117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1201444099 and 1201444108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201444163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600722066 + 600722067.
It is an arithmetic number, because the mean of its divisors is an integer number (600722067).
Almost surely, 21201444133 is an apocalyptic number.
It is an amenable number.
1201444133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201444133 is an equidigital number, since it uses as much as digits as its factorization.
1201444133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
The square root of 1201444133 is about 34661.8541483285. The cubic root of 1201444133 is about 1063.0846817128.
Adding to 1201444133 its reverse (3314441021), we get a palindrome (4515885154).
The spelling of 1201444133 in words is "one billion, two hundred one million, four hundred forty-four thousand, one hundred thirty-three".
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