1201453753 has 2 divisors, whose sum is σ = 1201453754. Its totient is φ = 1201453752.

The previous prime is 1201453741. The next prime is 1201453769. The reversal of 1201453753 is 3573541021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1006348729 + 195105024 = 31723^2 + 13968^2 .

It is an emirp because it is prime and its reverse (3573541021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1201453753 - 2²¹ = 1199356601 is a prime.

It is a super-2 number, since 2×1201453753² = 2886982241195570018, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1201453723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600726876 + 600726877.

It is an arithmetic number, because the mean of its divisors is an integer number (600726877).

Almost surely, 2^1201453753 is an apocalyptic number.

It is an amenable number.

1201453753 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201453753 is an equidigital number, since it uses as much as digits as its factorization.

1201453753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12600, while the sum is 31.

The square root of 1201453753 is about 34661.9929173151. The cubic root of 1201453753 is about 1063.0875190891.

Adding to 1201453753 its reverse (3573541021), we get a palindrome (4774994774).

The spelling of 1201453753 in words is "one billion, two hundred one million, four hundred fifty-three thousand, seven hundred fifty-three".