Base | Representation |
---|---|
bin | 11011010100011010101100… |
… | …110011010011100111011111 |
3 | 120202102020221222121002001012 |
4 | 123110122230303103213133 |
5 | 111222020320423103101 |
6 | 1103312143053205435 |
7 | 34210400536325045 |
oct | 3324325463234737 |
9 | 522366858532035 |
10 | 120150314269151 |
11 | 3531350a102431 |
12 | 11585b2919087b |
13 | 5207183b319ba |
14 | 219544046a395 |
15 | dd55bab11bbb |
hex | 6d46accd39df |
120150314269151 has 2 divisors, whose sum is σ = 120150314269152. Its totient is φ = 120150314269150.
The previous prime is 120150314269067. The next prime is 120150314269157. The reversal of 120150314269151 is 151962413051021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120150314269151 - 242 = 115752267758047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120150314269099 and 120150314269108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120150314269157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60075157134575 + 60075157134576.
It is an arithmetic number, because the mean of its divisors is an integer number (60075157134576).
Almost surely, 2120150314269151 is an apocalyptic number.
120150314269151 is a deficient number, since it is larger than the sum of its proper divisors (1).
120150314269151 is an equidigital number, since it uses as much as digits as its factorization.
120150314269151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 41.
The spelling of 120150314269151 in words is "one hundred twenty trillion, one hundred fifty billion, three hundred fourteen million, two hundred sixty-nine thousand, one hundred fifty-one".
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