Base | Representation |
---|---|
bin | 1010111011010111110110… |
… | …1000101011010110101101 |
3 | 1120112122011011100221011220 |
4 | 2232311331220223112231 |
5 | 3033323442110423003 |
6 | 41315401455133553 |
7 | 2350031104212654 |
oct | 256657550532655 |
9 | 46478134327156 |
10 | 12015131342253 |
11 | 3912652455236 |
12 | 14207432142b9 |
13 | 692039504340 |
14 | 2d776d43219b |
15 | 15c81b52b353 |
hex | aed7da2b5ad |
12015131342253 has 32 divisors (see below), whose sum is σ = 17296988403072. Its totient is φ = 7374862080000.
The previous prime is 12015131342251. The next prime is 12015131342281. The reversal of 12015131342253 is 35224313151021.
It is a happy number.
It is not a de Polignac number, because 12015131342253 - 21 = 12015131342251 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12015131342251) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 241237953 + ... + 241287753.
It is an arithmetic number, because the mean of its divisors is an integer number (540530887596).
Almost surely, 212015131342253 is an apocalyptic number.
12015131342253 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
12015131342253 is a deficient number, since it is larger than the sum of its proper divisors (5281857060819).
12015131342253 is a wasteful number, since it uses less digits than its factorization.
12015131342253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65645.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 12015131342253 its reverse (35224313151021), we get a palindrome (47239444493274).
The spelling of 12015131342253 in words is "twelve trillion, fifteen billion, one hundred thirty-one million, three hundred forty-two thousand, two hundred fifty-three".
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