1201610111521 has 2 divisors, whose sum is σ = 1201610111522. Its totient is φ = 1201610111520.

The previous prime is 1201610111519. The next prime is 1201610111561. The reversal of 1201610111521 is 1251110161021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1094984352225 + 106625759296 = 1046415^2 + 326536^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201610111521 - 2¹ = 1201610111519 is a prime.

Together with 1201610111519, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1201610111492 and 1201610111501.

It is not a weakly prime, because it can be changed into another prime (1201610111561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600805055760 + 600805055761.

It is an arithmetic number, because the mean of its divisors is an integer number (600805055761).

Almost surely, 2^{1201610111521} is an apocalyptic number.

It is an amenable number.

1201610111521 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201610111521 is an equidigital number, since it uses as much as digits as its factorization.

1201610111521 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 22.

Multiplying 1201610111521 by its sum of digits (22), we get a palindrome (26435422453462).

Adding to 1201610111521 its reverse (1251110161021), we get a palindrome (2452720272542).

It can be divided in two parts, 1201610 and 111521, that added together give a palindrome (1313131).

The spelling of 1201610111521 in words is "one trillion, two hundred one billion, six hundred ten million, one hundred eleven thousand, five hundred twenty-one".