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120201211019983 is a prime number
BaseRepresentation
bin11011010101001010000110…
…011111000000001011001111
3120202121010100001210220112211
4123111022012133000023033
5111223334040010114413
61103351401331211251
734214152030504522
oct3325120637001317
9522533301726484
10120201211019983
1135333057a88675
1211593972446b27
13520bc055cb202
142197aabd0cbb9
15dd6a9909083d
hex6d52867c02cf

120201211019983 has 2 divisors, whose sum is σ = 120201211019984. Its totient is φ = 120201211019982.

The previous prime is 120201211019947. The next prime is 120201211020083. The reversal of 120201211019983 is 389910112102021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120201211019983 - 241 = 118002187764431 is a prime.

It is a super-2 number, since 2×1202012110199832 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120201211019933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60100605509991 + 60100605509992.

It is an arithmetic number, because the mean of its divisors is an integer number (60100605509992).

Almost surely, 2120201211019983 is an apocalyptic number.

120201211019983 is a deficient number, since it is larger than the sum of its proper divisors (1).

120201211019983 is an equidigital number, since it uses as much as digits as its factorization.

120201211019983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 40.

The spelling of 120201211019983 in words is "one hundred twenty trillion, two hundred one billion, two hundred eleven million, nineteen thousand, nine hundred eighty-three".