Base | Representation |
---|---|
bin | 1010111011101010011100… |
… | …0110100100100101100001 |
3 | 1120120010000222012020001012 |
4 | 2232322213012210211201 |
5 | 3033414202213341001 |
6 | 41321545014350305 |
7 | 2350265554210355 |
oct | 256724706444541 |
9 | 46503028166035 |
10 | 12020122012001 |
11 | 391478356a294 |
12 | 14216b665b395 |
13 | 69265344716c |
14 | 2d7ac4185465 |
15 | 15ca0e73d2bb |
hex | aeea71a4961 |
12020122012001 has 2 divisors, whose sum is σ = 12020122012002. Its totient is φ = 12020122012000.
The previous prime is 12020122011977. The next prime is 12020122012021. The reversal of 12020122012001 is 10021022102021.
12020122012001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11843406030625 + 176715981376 = 3441425^2 + 420376^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12020122012001 is a prime.
It is not a weakly prime, because it can be changed into another prime (12020122012021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010061006000 + 6010061006001.
It is an arithmetic number, because the mean of its divisors is an integer number (6010061006001).
Almost surely, 212020122012001 is an apocalyptic number.
It is an amenable number.
12020122012001 is a deficient number, since it is larger than the sum of its proper divisors (1).
12020122012001 is an equidigital number, since it uses as much as digits as its factorization.
12020122012001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 12020122012001 its reverse (10021022102021), we get a palindrome (22041144114022).
The spelling of 12020122012001 in words is "twelve trillion, twenty billion, one hundred twenty-two million, twelve thousand, one".
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