Base | Representation |
---|---|
bin | 1010111011101010101111… |
… | …0000111010011000101001 |
3 | 1120120010020102100121112012 |
4 | 2232322223300322120221 |
5 | 3033414332224021301 |
6 | 41322000450525305 |
7 | 2350300524031535 |
oct | 256725360723051 |
9 | 46503212317465 |
10 | 12020200220201 |
11 | 3914813727268 |
12 | 1421718896835 |
13 | 6926666caac4 |
14 | 2d7ad0702bc5 |
15 | 15ca1653aebb |
hex | aeeabc3a629 |
12020200220201 has 2 divisors, whose sum is σ = 12020200220202. Its totient is φ = 12020200220200.
The previous prime is 12020200220173. The next prime is 12020200220209. The reversal of 12020200220201 is 10202200202021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10664894461225 + 1355305758976 = 3265715^2 + 1164176^2 .
It is a cyclic number.
It is not a de Polignac number, because 12020200220201 - 26 = 12020200220137 is a prime.
It is not a weakly prime, because it can be changed into another prime (12020200220209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010100110100 + 6010100110101.
It is an arithmetic number, because the mean of its divisors is an integer number (6010100110101).
Almost surely, 212020200220201 is an apocalyptic number.
It is an amenable number.
12020200220201 is a deficient number, since it is larger than the sum of its proper divisors (1).
12020200220201 is an equidigital number, since it uses as much as digits as its factorization.
12020200220201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 14.
Adding to 12020200220201 its reverse (10202200202021), we get a palindrome (22222400422222).
The spelling of 12020200220201 in words is "twelve trillion, twenty billion, two hundred million, two hundred twenty thousand, two hundred one".
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