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120202011122143 is a prime number
BaseRepresentation
bin11011010101001010110110…
…001011001001100111011111
3120202121012101211100022101011
4123111022312023021213133
5111223342204321402033
61103352012552200051
734214210614325056
oct3325126613114737
9522535354308334
10120202011122143
1135333428689225
1211593b56399027
13520c0022b8742
142197b462a339d
15dd6ae4437ccd
hex6d52b62c99df

120202011122143 has 2 divisors, whose sum is σ = 120202011122144. Its totient is φ = 120202011122142.

The previous prime is 120202011121999. The next prime is 120202011122189. The reversal of 120202011122143 is 341221110202021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120202011122143 - 29 = 120202011121631 is a prime.

It is a super-3 number, since 3×1202020111221433 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120902011122143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60101005561071 + 60101005561072.

It is an arithmetic number, because the mean of its divisors is an integer number (60101005561072).

Almost surely, 2120202011122143 is an apocalyptic number.

120202011122143 is a deficient number, since it is larger than the sum of its proper divisors (1).

120202011122143 is an equidigital number, since it uses as much as digits as its factorization.

120202011122143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 120202011122143 its reverse (341221110202021), we get a palindrome (461423121324164).

The spelling of 120202011122143 in words is "one hundred twenty trillion, two hundred two billion, eleven million, one hundred twenty-two thousand, one hundred forty-three".