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1202023010257 is a prime number
BaseRepresentation
bin10001011111011110001…
…001111000111111010001
311020220122001100200100021
4101133132021320333101
5124143220342312012
62320111324423441
7152562152002066
oct21373611707721
94226561320307
101202023010257
1142385871a6a3
12174b630a7b81
138947275a6b4
144226d092c6d
15214025e6007
hex117de278fd1

1202023010257 has 2 divisors, whose sum is σ = 1202023010258. Its totient is φ = 1202023010256.

The previous prime is 1202023010219. The next prime is 1202023010261. The reversal of 1202023010257 is 7520103202021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1197030739921 + 4992270336 = 1094089^2 + 70656^2 .

It is a cyclic number.

It is not a de Polignac number, because 1202023010257 - 27 = 1202023010129 is a prime.

It is a super-3 number, since 3×12020230102573 (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1202023010557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601011505128 + 601011505129.

It is an arithmetic number, because the mean of its divisors is an integer number (601011505129).

Almost surely, 21202023010257 is an apocalyptic number.

It is an amenable number.

1202023010257 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202023010257 is an equidigital number, since it uses as much as digits as its factorization.

1202023010257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1680, while the sum is 25.

Adding to 1202023010257 its reverse (7520103202021), we get a palindrome (8722126212278).

The spelling of 1202023010257 in words is "one trillion, two hundred two billion, twenty-three million, ten thousand, two hundred fifty-seven".