Base | Representation |
---|---|
bin | 10110011000111011… |
… | …10110010100001011 |
3 | 1011000201100002020002 |
4 | 23030131312110023 |
5 | 144104144430212 |
6 | 5304432553215 |
7 | 603605650244 |
oct | 131435662413 |
9 | 34021302202 |
10 | 12020311307 |
11 | 5109174884 |
12 | 23b56b280b |
13 | 1197426854 |
14 | 8205c7ccb |
15 | 4a5433ac2 |
hex | 2cc77650b |
12020311307 has 2 divisors, whose sum is σ = 12020311308. Its totient is φ = 12020311306.
The previous prime is 12020311291. The next prime is 12020311309. The reversal of 12020311307 is 70311302021.
It is a strong prime.
It is an emirp because it is prime and its reverse (70311302021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12020311307 - 24 = 12020311291 is a prime.
Together with 12020311309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12020311309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010155653 + 6010155654.
It is an arithmetic number, because the mean of its divisors is an integer number (6010155654).
Almost surely, 212020311307 is an apocalyptic number.
12020311307 is a deficient number, since it is larger than the sum of its proper divisors (1).
12020311307 is an equidigital number, since it uses as much as digits as its factorization.
12020311307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 12020311307 its reverse (70311302021), we get a palindrome (82331613328).
The spelling of 12020311307 in words is "twelve billion, twenty million, three hundred eleven thousand, three hundred seven".
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