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12020311307 is a prime number
BaseRepresentation
bin10110011000111011…
…10110010100001011
31011000201100002020002
423030131312110023
5144104144430212
65304432553215
7603605650244
oct131435662413
934021302202
1012020311307
115109174884
1223b56b280b
131197426854
148205c7ccb
154a5433ac2
hex2cc77650b

12020311307 has 2 divisors, whose sum is σ = 12020311308. Its totient is φ = 12020311306.

The previous prime is 12020311291. The next prime is 12020311309. The reversal of 12020311307 is 70311302021.

It is a strong prime.

It is an emirp because it is prime and its reverse (70311302021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12020311307 - 24 = 12020311291 is a prime.

Together with 12020311309, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12020311309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010155653 + 6010155654.

It is an arithmetic number, because the mean of its divisors is an integer number (6010155654).

Almost surely, 212020311307 is an apocalyptic number.

12020311307 is a deficient number, since it is larger than the sum of its proper divisors (1).

12020311307 is an equidigital number, since it uses as much as digits as its factorization.

12020311307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 20.

Adding to 12020311307 its reverse (70311302021), we get a palindrome (82331613328).

The spelling of 12020311307 in words is "twelve billion, twenty million, three hundred eleven thousand, three hundred seven".