1202034113141 has 2 divisors, whose sum is σ = 1202034113142. Its totient is φ = 1202034113140.

The previous prime is 1202034113107. The next prime is 1202034113167. The reversal of 1202034113141 is 1413114302021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 604576227025 + 597457886116 = 777545^2 + 772954^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1202034113141 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1202034110141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601017056570 + 601017056571.

It is an arithmetic number, because the mean of its divisors is an integer number (601017056571).

Almost surely, 2^{1202034113141} is an apocalyptic number.

It is an amenable number.

1202034113141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202034113141 is an equidigital number, since it uses as much as digits as its factorization.

1202034113141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1202034113141 its reverse (1413114302021), we get a palindrome (2615148415162).

The spelling of 1202034113141 in words is "one trillion, two hundred two billion, thirty-four million, one hundred thirteen thousand, one hundred forty-one".