Base | Representation |
---|---|
bin | 100011110100101… |
… | …1001010111001001 |
3 | 10002202211122211021 |
4 | 1013221121113021 |
5 | 4430210042441 |
6 | 315135432441 |
7 | 41534056441 |
oct | 10751312711 |
9 | 3082748737 |
10 | 1202034121 |
11 | 567576032 |
12 | 296685721 |
13 | 1620572c2 |
14 | b58dd121 |
15 | 707dd3d1 |
hex | 47a595c9 |
1202034121 has 2 divisors, whose sum is σ = 1202034122. Its totient is φ = 1202034120.
The previous prime is 1202034109. The next prime is 1202034139. The reversal of 1202034121 is 1214302021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1052094096 + 149940025 = 32436^2 + 12245^2 .
It is an emirp because it is prime and its reverse (1214302021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1202034121 - 229 = 665163209 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1202034095 and 1202034104.
It is not a weakly prime, because it can be changed into another prime (1202034101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601017060 + 601017061.
It is an arithmetic number, because the mean of its divisors is an integer number (601017061).
Almost surely, 21202034121 is an apocalyptic number.
It is an amenable number.
1202034121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202034121 is an equidigital number, since it uses as much as digits as its factorization.
1202034121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 16.
The square root of 1202034121 is about 34670.3637275411. The cubic root of 1202034121 is about 1063.2586680429.
Adding to 1202034121 its reverse (1214302021), we get a palindrome (2416336142).
The spelling of 1202034121 in words is "one billion, two hundred two million, thirty-four thousand, one hundred twenty-one".
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