1202043380443 has 2 divisors, whose sum is σ = 1202043380444. Its totient is φ = 1202043380442.

The previous prime is 1202043380411. The next prime is 1202043380497. The reversal of 1202043380443 is 3440833402021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1202043380443 - 2⁵ = 1202043380411 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1202043380399 and 1202043380408.

It is not a weakly prime, because it can be changed into another prime (1202043386443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601021690221 + 601021690222.

It is an arithmetic number, because the mean of its divisors is an integer number (601021690222).

Almost surely, 2^{1202043380443} is an apocalyptic number.

1202043380443 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202043380443 is an equidigital number, since it uses as much as digits as its factorization.

1202043380443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 1202043380443 its reverse (3440833402021), we get a palindrome (4642876782464).

The spelling of 1202043380443 in words is "one trillion, two hundred two billion, forty-three million, three hundred eighty thousand, four hundred forty-three".