12020513331412 has 12 divisors (see below), whose sum is σ = 21483470635200. Its totient is φ = 5882378864216.

The previous prime is 12020513331371. The next prime is 12020513331413. The reversal of 12020513331412 is 21413331502021.

It is a super-3 number, since 3×12020513331412³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12020513331413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31969450162 + ... + 31969450537.

It is an arithmetic number, because the mean of its divisors is an integer number (1790289219600).

Almost surely, 2^{12020513331412} is an apocalyptic number.

It is an amenable number.

12020513331412 is a deficient number, since it is larger than the sum of its proper divisors (9462957303788).

12020513331412 is a wasteful number, since it uses less digits than its factorization.

12020513331412 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63938900750 (or 63938900748 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 12020513331412 its reverse (21413331502021), we get a palindrome (33433844833433).

The spelling of 12020513331412 in words is "twelve trillion, twenty billion, five hundred thirteen million, three hundred thirty-one thousand, four hundred twelve".