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120209516935213 is a prime number
BaseRepresentation
bin11011010101010001110101…
…100011100011100000101101
3120202121220202220212010020211
4123111101311203203200231
5111224003042313411323
61103355253435542421
734214564614562026
oct3325216543434055
9522556686763224
10120209516935213
113533662a4aa722
12115954abbbaa11
13520c92a330654
142198259089c4d
15dd6dd336770d
hex6d54758e382d

120209516935213 has 2 divisors, whose sum is σ = 120209516935214. Its totient is φ = 120209516935212.

The previous prime is 120209516935141. The next prime is 120209516935217. The reversal of 120209516935213 is 312539615902021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110559715208644 + 9649801726569 = 10514738^2 + 3106413^2 .

It is a cyclic number.

It is not a de Polignac number, because 120209516935213 - 233 = 120200927000621 is a prime.

It is a super-2 number, since 2×1202095169352132 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120209516935217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60104758467606 + 60104758467607.

It is an arithmetic number, because the mean of its divisors is an integer number (60104758467607).

Almost surely, 2120209516935213 is an apocalyptic number.

It is an amenable number.

120209516935213 is a deficient number, since it is larger than the sum of its proper divisors (1).

120209516935213 is an equidigital number, since it uses as much as digits as its factorization.

120209516935213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 874800, while the sum is 49.

The spelling of 120209516935213 in words is "one hundred twenty trillion, two hundred nine billion, five hundred sixteen million, nine hundred thirty-five thousand, two hundred thirteen".