Base | Representation |
---|---|
bin | 10001011111100010110… |
… | …100001010110001100001 |
3 | 11020220211111111020021101 |
4 | 101133202310022301201 |
5 | 124143400401431032 |
6 | 2320123200354401 |
7 | 152564121424312 |
oct | 21374264126141 |
9 | 4226744436241 |
10 | 1202101202017 |
11 | 423898876291 |
12 | 174b85315a01 |
13 | 89485a06a01 |
14 | 42279608609 |
15 | 214093ddde7 |
hex | 117e2d0ac61 |
1202101202017 has 2 divisors, whose sum is σ = 1202101202018. Its totient is φ = 1202101202016.
The previous prime is 1202101201981. The next prime is 1202101202051. The reversal of 1202101202017 is 7102021012021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 833001210721 + 369099991296 = 912689^2 + 607536^2 .
It is a cyclic number.
It is not a de Polignac number, because 1202101202017 - 215 = 1202101169249 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1202101201985 and 1202101202003.
It is not a weakly prime, because it can be changed into another prime (1202101202117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601050601008 + 601050601009.
It is an arithmetic number, because the mean of its divisors is an integer number (601050601009).
Almost surely, 21202101202017 is an apocalyptic number.
It is an amenable number.
1202101202017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202101202017 is an equidigital number, since it uses as much as digits as its factorization.
1202101202017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 1202101202017 its reverse (7102021012021), we get a palindrome (8304122214038).
The spelling of 1202101202017 in words is "one trillion, two hundred two billion, one hundred one million, two hundred two thousand, seventeen".
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