Base | Representation |
---|---|
bin | 10001011111100011011… |
… | …010010111000110000101 |
3 | 11020220212012022220001222 |
4 | 101133203122113012011 |
5 | 124143410432321312 |
6 | 2320124155130125 |
7 | 152564302503533 |
oct | 21374332270605 |
9 | 4226765286058 |
10 | 1202111213957 |
11 | 4238a3494415 |
12 | 174b88743945 |
13 | 89487b00b34 |
14 | 4227aa93153 |
15 | 2140a21a672 |
hex | 117e3697185 |
1202111213957 has 2 divisors, whose sum is σ = 1202111213958. Its totient is φ = 1202111213956.
The previous prime is 1202111213929. The next prime is 1202111213969. The reversal of 1202111213957 is 7593121112021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1202024984161 + 86229796 = 1096369^2 + 9286^2 .
It is a cyclic number.
It is not a de Polignac number, because 1202111213957 - 26 = 1202111213893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1202111213917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601055606978 + 601055606979.
It is an arithmetic number, because the mean of its divisors is an integer number (601055606979).
Almost surely, 21202111213957 is an apocalyptic number.
It is an amenable number.
1202111213957 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202111213957 is an equidigital number, since it uses as much as digits as its factorization.
1202111213957 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 35.
Adding to 1202111213957 its reverse (7593121112021), we get a palindrome (8795232325978).
The spelling of 1202111213957 in words is "one trillion, two hundred two billion, one hundred eleven million, two hundred thirteen thousand, nine hundred fifty-seven".
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