Base | Representation |
---|---|
bin | 110111111110100100… |
… | …1110000111001100111 |
3 | 102111021201210101101101 |
4 | 1233331021300321213 |
5 | 3432143043442411 |
6 | 131120241340531 |
7 | 11453643203023 |
oct | 1577511607147 |
9 | 374251711341 |
10 | 120211312231 |
11 | 46a8817412a |
12 | 1b36a637747 |
13 | b449c025aa |
14 | 5b65431383 |
15 | 31d87e68c1 |
hex | 1bfd270e67 |
120211312231 has 2 divisors, whose sum is σ = 120211312232. Its totient is φ = 120211312230.
The previous prime is 120211312201. The next prime is 120211312241. The reversal of 120211312231 is 132213112021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120211312231 - 27 = 120211312103 is a prime.
It is a super-2 number, since 2×1202113122312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120211312199 and 120211312208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120211312201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60105656115 + 60105656116.
It is an arithmetic number, because the mean of its divisors is an integer number (60105656116).
Almost surely, 2120211312231 is an apocalyptic number.
120211312231 is a deficient number, since it is larger than the sum of its proper divisors (1).
120211312231 is an equidigital number, since it uses as much as digits as its factorization.
120211312231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 120211312231 its reverse (132213112021), we get a palindrome (252424424252).
The spelling of 120211312231 in words is "one hundred twenty billion, two hundred eleven million, three hundred twelve thousand, two hundred thirty-one".
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