120211321442431 has 2 divisors, whose sum is σ = 120211321442432. Its totient is φ = 120211321442430.

The previous prime is 120211321442413. The next prime is 120211321442441. The reversal of 120211321442431 is 134244123112021.

Together with previous prime (120211321442413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120211321442431 - 2²³ = 120211313053823 is a prime.

It is a super-2 number, since 2×120211321442431² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120211321442393 and 120211321442402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120211321442441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60105660721215 + 60105660721216.

It is an arithmetic number, because the mean of its divisors is an integer number (60105660721216).

Almost surely, 2^{120211321442431} is an apocalyptic number.

120211321442431 is a deficient number, since it is larger than the sum of its proper divisors (1).

120211321442431 is an equidigital number, since it uses as much as digits as its factorization.

120211321442431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 120211321442431 its reverse (134244123112021), we get a palindrome (254455444554452).

The spelling of 120211321442431 in words is "one hundred twenty trillion, two hundred eleven billion, three hundred twenty-one million, four hundred forty-two thousand, four hundred thirty-one".