Base | Representation |
---|---|
bin | 1010111011101110010000… |
… | …0101100010111100101111 |
3 | 1120120012200021102012002101 |
4 | 2232323210011202330233 |
5 | 3033423301124401302 |
6 | 41322234324035531 |
7 | 2350333116602602 |
oct | 256734405427457 |
9 | 46505607365071 |
10 | 12021145153327 |
11 | 3915159059532 |
12 | 1421941232ba7 |
13 | 6927873c752b |
14 | 2d7b7ddd8339 |
15 | 15ca6e491287 |
hex | aeee4162f2f |
12021145153327 has 2 divisors, whose sum is σ = 12021145153328. Its totient is φ = 12021145153326.
The previous prime is 12021145153291. The next prime is 12021145153349. The reversal of 12021145153327 is 72335154112021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12021145153327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12021145153397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010572576663 + 6010572576664.
It is an arithmetic number, because the mean of its divisors is an integer number (6010572576664).
Almost surely, 212021145153327 is an apocalyptic number.
12021145153327 is a deficient number, since it is larger than the sum of its proper divisors (1).
12021145153327 is an equidigital number, since it uses as much as digits as its factorization.
12021145153327 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50400, while the sum is 37.
Adding to 12021145153327 its reverse (72335154112021), we get a palindrome (84356299265348).
It can be divided in two parts, 1202114 and 5153327, that added together give a square (6355441 = 25212).
The spelling of 12021145153327 in words is "twelve trillion, twenty-one billion, one hundred forty-five million, one hundred fifty-three thousand, three hundred twenty-seven".
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