Base | Representation |
---|---|
bin | 1010111011101110010000… |
… | …0111100010111100010011 |
3 | 1120120012200022101211020102 |
4 | 2232323210013202330103 |
5 | 3033423301243140322 |
6 | 41322234343203015 |
7 | 2350333124215214 |
oct | 256734407427423 |
9 | 46505608354212 |
10 | 12021145677587 |
11 | 3915159387402 |
12 | 142194144646b |
13 | 69278754c047 |
14 | 2d7b800d340b |
15 | 15ca6e546792 |
hex | aeee41e2f13 |
12021145677587 has 2 divisors, whose sum is σ = 12021145677588. Its totient is φ = 12021145677586.
The previous prime is 12021145677577. The next prime is 12021145677643. The reversal of 12021145677587 is 78577654112021.
It is an a-pointer prime, because the next prime (12021145677643) can be obtained adding 12021145677587 to its sum of digits (56).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12021145677587 - 212 = 12021145673491 is a prime.
It is a super-2 number, since 2×120211456775872 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12021145677577) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010572838793 + 6010572838794.
It is an arithmetic number, because the mean of its divisors is an integer number (6010572838794).
Almost surely, 212021145677587 is an apocalyptic number.
12021145677587 is a deficient number, since it is larger than the sum of its proper divisors (1).
12021145677587 is an equidigital number, since it uses as much as digits as its factorization.
12021145677587 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6585600, while the sum is 56.
The spelling of 12021145677587 in words is "twelve trillion, twenty-one billion, one hundred forty-five million, six hundred seventy-seven thousand, five hundred eighty-seven".
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