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120211479385093 is a prime number
BaseRepresentation
bin11011010101010011101010…
…100001101101010000000101
3120202122002211200112220101201
4123111103222201231100011
5111224021102210310333
61103400220302022501
734214664344251165
oct3325235241552005
9522562750486351
10120211479385093
113533744722a328
1211595959277a31
13520cb80a8b2b5
1421983a396c5a5
15dd6e9a7ae17d
hex6d54ea86d405

120211479385093 has 2 divisors, whose sum is σ = 120211479385094. Its totient is φ = 120211479385092.

The previous prime is 120211479385087. The next prime is 120211479385121. The reversal of 120211479385093 is 390583974112021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85578466244769 + 34633013140324 = 9250863^2 + 5884982^2 .

It is a cyclic number.

It is not a de Polignac number, because 120211479385093 - 225 = 120211445830661 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120211479335093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60105739692546 + 60105739692547.

It is an arithmetic number, because the mean of its divisors is an integer number (60105739692547).

Almost surely, 2120211479385093 is an apocalyptic number.

It is an amenable number.

120211479385093 is a deficient number, since it is larger than the sum of its proper divisors (1).

120211479385093 is an equidigital number, since it uses as much as digits as its factorization.

120211479385093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3265920, while the sum is 55.

The spelling of 120211479385093 in words is "one hundred twenty trillion, two hundred eleven billion, four hundred seventy-nine million, three hundred eighty-five thousand, ninety-three".