Base | Representation |
---|---|
bin | 10110011001000010… |
… | …00111100011010111 |
3 | 1011000202221121212011 |
4 | 23030201013203113 |
5 | 144104404341333 |
6 | 5304503205051 |
7 | 603616150012 |
oct | 131441074327 |
9 | 34022847764 |
10 | 12021168343 |
11 | 51096aa778 |
12 | 23b5a46787 |
13 | 1197666982 |
14 | 82076c379 |
15 | 4a55529cd |
hex | 2cc8478d7 |
12021168343 has 2 divisors, whose sum is σ = 12021168344. Its totient is φ = 12021168342.
The previous prime is 12021168331. The next prime is 12021168359. The reversal of 12021168343 is 34386112021.
12021168343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12021168343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12021168043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010584171 + 6010584172.
It is an arithmetic number, because the mean of its divisors is an integer number (6010584172).
Almost surely, 212021168343 is an apocalyptic number.
12021168343 is a deficient number, since it is larger than the sum of its proper divisors (1).
12021168343 is an equidigital number, since it uses as much as digits as its factorization.
12021168343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 12021168343 in words is "twelve billion, twenty-one million, one hundred sixty-eight thousand, three hundred forty-three".
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