Base | Representation |
---|---|
bin | 110111111110100110… |
… | …0010011010001111111 |
3 | 102111021210001011202011 |
4 | 1233331030103101333 |
5 | 3432143231233333 |
6 | 131120303512051 |
7 | 11453651643103 |
oct | 1577514232177 |
9 | 374253034664 |
10 | 120211977343 |
11 | 46a88588907 |
12 | 1b36a8b8627 |
13 | b44a0a6253 |
14 | 5b65565903 |
15 | 31d88c89cd |
hex | 1bfd31347f |
120211977343 has 2 divisors, whose sum is σ = 120211977344. Its totient is φ = 120211977342.
The previous prime is 120211977337. The next prime is 120211977359. The reversal of 120211977343 is 343779112021.
It is a weak prime.
It is an emirp because it is prime and its reverse (343779112021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120211977343 - 233 = 111622042751 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120211977296 and 120211977305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120211977323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60105988671 + 60105988672.
It is an arithmetic number, because the mean of its divisors is an integer number (60105988672).
Almost surely, 2120211977343 is an apocalyptic number.
120211977343 is a deficient number, since it is larger than the sum of its proper divisors (1).
120211977343 is an equidigital number, since it uses as much as digits as its factorization.
120211977343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63504, while the sum is 40.
The spelling of 120211977343 in words is "one hundred twenty billion, two hundred eleven million, nine hundred seventy-seven thousand, three hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •