Base | Representation |
---|---|
bin | 10001011111100011111… |
… | …100010101111000101101 |
3 | 11020220212211002110110211 |
4 | 101133203330111320231 |
5 | 124143420222400101 |
6 | 2320125114102421 |
7 | 152564441304316 |
oct | 21374374257055 |
9 | 4226784073424 |
10 | 1202120121901 |
11 | 4238a8519056 |
12 | 174b8b71aa11 |
13 | 894898cc5ca |
14 | 4227bd3160d |
15 | 2140adc9c51 |
hex | 117e3f15e2d |
1202120121901 has 2 divisors, whose sum is σ = 1202120121902. Its totient is φ = 1202120121900.
The previous prime is 1202120121889. The next prime is 1202120121907. The reversal of 1202120121901 is 1091210212021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1128111639876 + 74008482025 = 1062126^2 + 272045^2 .
It is an emirp because it is prime and its reverse (1091210212021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1202120121901 - 215 = 1202120089133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1202120121907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601060060950 + 601060060951.
It is an arithmetic number, because the mean of its divisors is an integer number (601060060951).
Almost surely, 21202120121901 is an apocalyptic number.
It is an amenable number.
1202120121901 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202120121901 is an equidigital number, since it uses as much as digits as its factorization.
1202120121901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 1202120121901 its reverse (1091210212021), we get a palindrome (2293330333922).
The spelling of 1202120121901 in words is "one trillion, two hundred two billion, one hundred twenty million, one hundred twenty-one thousand, nine hundred one".
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