Base | Representation |
---|---|
bin | 1010111011101110011101… |
… | …1011110101111101010000 |
3 | 1120120012211012010020222220 |
4 | 2232323213123311331100 |
5 | 3033423410020030000 |
6 | 41322244052101040 |
7 | 2350334401234152 |
oct | 256734733657520 |
9 | 46505735106886 |
10 | 12021201330000 |
11 | 3915187838935 |
12 | 1421958004780 |
13 | 692795c36175 |
14 | 2d7b8765cad2 |
15 | 15ca7438b1a0 |
hex | aeee76f5f50 |
12021201330000 has 200 divisors, whose sum is σ = 41088750740928. Its totient is φ = 3017085696000.
The previous prime is 12021201329989. The next prime is 12021201330013. The reversal of 12021201330000 is 3310212021.
It is a tau number, because it is divible by the number of its divisors (200).
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 11275492 + ... + 12295491.
Almost surely, 212021201330000 is an apocalyptic number.
12021201330000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12021201330000 is an abundant number, since it is smaller than the sum of its proper divisors (29067549410928).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12021201330000 is a wasteful number, since it uses less digits than its factorization.
12021201330000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23571031 (or 23571010 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 12021201330000 its reverse (3310212021), we get a palindrome (12024511542021).
The spelling of 12021201330000 in words is "twelve trillion, twenty-one billion, two hundred one million, three hundred thirty thousand".
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