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12021201330000 = 243541723570983
BaseRepresentation
bin1010111011101110011101…
…1011110101111101010000
31120120012211012010020222220
42232323213123311331100
53033423410020030000
641322244052101040
72350334401234152
oct256734733657520
946505735106886
1012021201330000
113915187838935
121421958004780
13692795c36175
142d7b8765cad2
1515ca7438b1a0
hexaeee76f5f50

12021201330000 has 200 divisors, whose sum is σ = 41088750740928. Its totient is φ = 3017085696000.

The previous prime is 12021201329989. The next prime is 12021201330013. The reversal of 12021201330000 is 3310212021.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 11275492 + ... + 12295491.

Almost surely, 212021201330000 is an apocalyptic number.

12021201330000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12021201330000 is an abundant number, since it is smaller than the sum of its proper divisors (29067549410928).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12021201330000 is a wasteful number, since it uses less digits than its factorization.

12021201330000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23571031 (or 23571010 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 12021201330000 its reverse (3310212021), we get a palindrome (12024511542021).

The spelling of 12021201330000 in words is "twelve trillion, twenty-one billion, two hundred one million, three hundred thirty thousand".