Base | Representation |
---|---|
bin | 110111111110100110… |
… | …0100011100011111011 |
3 | 102111021210011120012221 |
4 | 1233331030203203323 |
5 | 3432143240402102 |
6 | 131120305144511 |
7 | 11453652341365 |
oct | 1577514434373 |
9 | 374253146187 |
10 | 120212044027 |
11 | 46a88623a19 |
12 | 1b36a92b137 |
13 | b44a0ca6ca |
14 | 5b65581d35 |
15 | 31d88dd637 |
hex | 1bfd3238fb |
120212044027 has 2 divisors, whose sum is σ = 120212044028. Its totient is φ = 120212044026.
The previous prime is 120212044009. The next prime is 120212044049. The reversal of 120212044027 is 720440212021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120212044027 - 27 = 120212043899 is a prime.
It is a super-3 number, since 3×1202120440273 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120212043992 and 120212044010.
It is not a weakly prime, because it can be changed into another prime (120212044097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60106022013 + 60106022014.
It is an arithmetic number, because the mean of its divisors is an integer number (60106022014).
Almost surely, 2120212044027 is an apocalyptic number.
120212044027 is a deficient number, since it is larger than the sum of its proper divisors (1).
120212044027 is an equidigital number, since it uses as much as digits as its factorization.
120212044027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1792, while the sum is 25.
Adding to 120212044027 its reverse (720440212021), we get a palindrome (840652256048).
The spelling of 120212044027 in words is "one hundred twenty billion, two hundred twelve million, forty-four thousand, twenty-seven".
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