Base | Representation |
---|---|
bin | 10001011111100100101… |
… | …001101111001101110111 |
3 | 11020220220122111001112020 |
4 | 101133210221233031313 |
5 | 124143431244202020 |
6 | 2320130221124223 |
7 | 152564644410012 |
oct | 21374451571567 |
9 | 4226818431466 |
10 | 1202132022135 |
11 | 423904206960 |
12 | 174b936b9673 |
13 | 8948c208075 |
14 | 4227d74c379 |
15 | 2140be7ac40 |
hex | 117e4a6f377 |
1202132022135 has 32 divisors (see below), whose sum is σ = 2099468374272. Its totient is φ = 582518119680.
The previous prime is 1202132022073. The next prime is 1202132022269. The reversal of 1202132022135 is 5312202312021.
It is not a de Polignac number, because 1202132022135 - 215 = 1202131989367 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1796934 + ... + 2373443.
It is an arithmetic number, because the mean of its divisors is an integer number (65608386696).
Almost surely, 21202132022135 is an apocalyptic number.
1202132022135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1202132022135 is a deficient number, since it is larger than the sum of its proper divisors (897336352137).
1202132022135 is a wasteful number, since it uses less digits than its factorization.
1202132022135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4172143.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 1202132022135 its reverse (5312202312021), we get a palindrome (6514334334156).
The spelling of 1202132022135 in words is "one trillion, two hundred two billion, one hundred thirty-two million, twenty-two thousand, one hundred thirty-five".
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