12021434044130 has 32 divisors (see below), whose sum is σ = 24756199848576. Its totient is φ = 4117235750784.

The previous prime is 12021434044127. The next prime is 12021434044181. The reversal of 12021434044130 is 3144043412021.

It is a junction number, because it is equal to n+sod(n) for n = 12021434044093 and 12021434044102.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 91575164 + ... + 91706343.

It is an arithmetic number, because the mean of its divisors is an integer number (773631245268).

Almost surely, 2^{12021434044130} is an apocalyptic number.

12021434044130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12021434044130 is an abundant number, since it is smaller than the sum of its proper divisors (12734765804446).

12021434044130 is a wasteful number, since it uses less digits than its factorization.

12021434044130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 183282458.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 12021434044130 its reverse (3144043412021), we get a palindrome (15165477456151).

The spelling of 12021434044130 in words is "twelve trillion, twenty-one billion, four hundred thirty-four million, forty-four thousand, one hundred thirty".