Base | Representation |
---|---|
bin | 1010111011110001011110… |
… | …1001000100010101010001 |
3 | 1120120021220112222012010221 |
4 | 2232330113221010111101 |
5 | 3033432034041244441 |
6 | 41322500222553041 |
7 | 2350363421550244 |
oct | 256742751042521 |
9 | 46507815865127 |
10 | 12022010103121 |
11 | 3915562321077 |
12 | 1421b42a38781 |
13 | 69289466b345 |
14 | 2d7c22c2d25b |
15 | 15cac03978d1 |
hex | aef17a44551 |
12022010103121 has 2 divisors, whose sum is σ = 12022010103122. Its totient is φ = 12022010103120.
The previous prime is 12022010103091. The next prime is 12022010103137. The reversal of 12022010103121 is 12130101022021.
12022010103121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an a-pointer prime, because the next prime (12022010103137) can be obtained adding 12022010103121 to its sum of digits (16).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9428737890625 + 2593272212496 = 3070625^2 + 1610364^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12022010103121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12022010103095 and 12022010103104.
It is not a weakly prime, because it can be changed into another prime (12022010103721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011005051560 + 6011005051561.
It is an arithmetic number, because the mean of its divisors is an integer number (6011005051561).
Almost surely, 212022010103121 is an apocalyptic number.
It is an amenable number.
12022010103121 is a deficient number, since it is larger than the sum of its proper divisors (1).
12022010103121 is an equidigital number, since it uses as much as digits as its factorization.
12022010103121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 12022010103121 its reverse (12130101022021), we get a palindrome (24152111125142).
The spelling of 12022010103121 in words is "twelve trillion, twenty-two billion, ten million, one hundred three thousand, one hundred twenty-one".
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