Base | Representation |
---|---|
bin | 1010111011110001110100… |
… | …0111101010100010111111 |
3 | 1120120022010221220112202011 |
4 | 2232330131013222202333 |
5 | 3033432231103310142 |
6 | 41322513304512051 |
7 | 2350365616004413 |
oct | 256743507524277 |
9 | 46508127815664 |
10 | 12022102010047 |
11 | 39155aa195108 |
12 | 1421b6977b627 |
13 | 6928aa70a23c |
14 | 2d7c31114d43 |
15 | 15cac849e417 |
hex | aef1d1ea8bf |
12022102010047 has 2 divisors, whose sum is σ = 12022102010048. Its totient is φ = 12022102010046.
The previous prime is 12022102009997. The next prime is 12022102010057. The reversal of 12022102010047 is 74001020122021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12022102010047 - 235 = 11987742271679 is a prime.
It is a super-2 number, since 2×120221020100472 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12022102010057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011051005023 + 6011051005024.
It is an arithmetic number, because the mean of its divisors is an integer number (6011051005024).
Almost surely, 212022102010047 is an apocalyptic number.
12022102010047 is a deficient number, since it is larger than the sum of its proper divisors (1).
12022102010047 is an equidigital number, since it uses as much as digits as its factorization.
12022102010047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 22.
Adding to 12022102010047 its reverse (74001020122021), we get a palindrome (86023122132068).
The spelling of 12022102010047 in words is "twelve trillion, twenty-two billion, one hundred two million, ten thousand, forty-seven".
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