Base | Representation |
---|---|
bin | 110111111110110111… |
… | …1000110101111111011 |
3 | 102111022102012201010021 |
4 | 1233331233012233323 |
5 | 3432203100213201 |
6 | 131121231231311 |
7 | 11454122332612 |
oct | 1577557065773 |
9 | 374272181107 |
10 | 120221101051 |
11 | 46a9274a667 |
12 | 1b371978537 |
13 | b44bc4bcac |
14 | 5b6685c879 |
15 | 31d95cbea1 |
hex | 1bfdbc6bfb |
120221101051 has 2 divisors, whose sum is σ = 120221101052. Its totient is φ = 120221101050.
The previous prime is 120221101009. The next prime is 120221101067. The reversal of 120221101051 is 150101122021.
It is an a-pointer prime, because the next prime (120221101067) can be obtained adding 120221101051 to its sum of digits (16).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120221101051 - 215 = 120221068283 is a prime.
It is a super-2 number, since 2×1202211010512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120221107051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60110550525 + 60110550526.
It is an arithmetic number, because the mean of its divisors is an integer number (60110550526).
Almost surely, 2120221101051 is an apocalyptic number.
120221101051 is a deficient number, since it is larger than the sum of its proper divisors (1).
120221101051 is an equidigital number, since it uses as much as digits as its factorization.
120221101051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 120221101051 its reverse (150101122021), we get a palindrome (270322223072).
The spelling of 120221101051 in words is "one hundred twenty billion, two hundred twenty-one million, one hundred one thousand, fifty-one".
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