Search a number
-
+
120221220011112 = 233211296164384913
BaseRepresentation
bin11011010101011100101111…
…000111001111110001101000
3120202200000222112020222022100
4123111130233013033301220
5111224201024310323422
61103404511021253400
734215460622226603
oct3325345707176150
9522600875228270
10120221220011112
1135340595598880
1211597817404260
135210a73b0342c
142198a4949533a
15dd736a9d57ac
hex6d572f1cfc68

120221220011112 has 192 divisors, whose sum is σ = 367457590843200. Its totient is φ = 35173457786880.

The previous prime is 120221220011089. The next prime is 120221220011119. The reversal of 120221220011112 is 211110022122021.

120221220011112 is a `hidden beast` number, since 120 + 221 + 2 + 200 + 11 + 112 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (120221220011119) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1415773968 + ... + 1415858880.

It is an arithmetic number, because the mean of its divisors is an integer number (1913841618975).

Almost surely, 2120221220011112 is an apocalyptic number.

120221220011112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120221220011112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (183728795421600).

120221220011112 is an abundant number, since it is smaller than the sum of its proper divisors (247236370832088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120221220011112 is a wasteful number, since it uses less digits than its factorization.

120221220011112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 146608 (or 146601 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 18.

Adding to 120221220011112 its reverse (211110022122021), we get a palindrome (331331242133133).

The spelling of 120221220011112 in words is "one hundred twenty trillion, two hundred twenty-one billion, two hundred twenty million, eleven thousand, one hundred twelve".