120221345533 has 2 divisors, whose sum is σ = 120221345534. Its totient is φ = 120221345532.

The previous prime is 120221345527. The next prime is 120221345537. The reversal of 120221345533 is 335543122021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117932488569 + 2288856964 = 343413^2 + 47842^2 .

It is an emirp because it is prime and its reverse (335543122021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120221345533 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120221345495 and 120221345504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120221345537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60110672766 + 60110672767.

It is an arithmetic number, because the mean of its divisors is an integer number (60110672767).

Almost surely, 2^120221345533 is an apocalyptic number.

It is an amenable number.

120221345533 is a deficient number, since it is larger than the sum of its proper divisors (1).

120221345533 is an equidigital number, since it uses as much as digits as its factorization.

120221345533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 120221345533 its reverse (335543122021), we get a palindrome (455764467554).

The spelling of 120221345533 in words is "one hundred twenty billion, two hundred twenty-one million, three hundred forty-five thousand, five hundred thirty-three".