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12022135241 is a prime number
BaseRepresentation
bin10110011001001001…
…10011100111001001
31011000211202202012012
423030210303213021
5144110131311431
65304540025305
7603630314654
oct131444634711
934024682165
1012022135241
11510a200166
1223b6232235
131197914abc
1482094089b
154a569422b
hex2cc9339c9

12022135241 has 2 divisors, whose sum is σ = 12022135242. Its totient is φ = 12022135240.

The previous prime is 12022135231. The next prime is 12022135243. The reversal of 12022135241 is 14253122021.

12022135241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11963765641 + 58369600 = 109379^2 + 7640^2 .

It is a cyclic number.

It is not a de Polignac number, because 12022135241 - 210 = 12022134217 is a prime.

Together with 12022135243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12022135243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011067620 + 6011067621.

It is an arithmetic number, because the mean of its divisors is an integer number (6011067621).

Almost surely, 212022135241 is an apocalyptic number.

It is an amenable number.

12022135241 is a deficient number, since it is larger than the sum of its proper divisors (1).

12022135241 is an equidigital number, since it uses as much as digits as its factorization.

12022135241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 12022135241 its reverse (14253122021), we get a palindrome (26275257262).

The spelling of 12022135241 in words is "twelve billion, twenty-two million, one hundred thirty-five thousand, two hundred forty-one".