Base | Representation |
---|---|
bin | 11011010101011110100000… |
… | …111101101001111000011011 |
3 | 120202200012220122102111121121 |
4 | 123111132200331221320123 |
5 | 111224213432301133402 |
6 | 1103405424333150111 |
7 | 34215556144553611 |
oct | 3325364075517033 |
9 | 522605818374547 |
10 | 120223130099227 |
11 | 353413858042a1 |
12 | 1159806b02b337 |
13 | 5210cb975999c |
14 | 2198b8b0276b1 |
15 | dd742d537837 |
hex | 6d57a0f69e1b |
120223130099227 has 2 divisors, whose sum is σ = 120223130099228. Its totient is φ = 120223130099226.
The previous prime is 120223130099183. The next prime is 120223130099249. The reversal of 120223130099227 is 722990031322021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120223130099227 - 211 = 120223130097179 is a prime.
It is a super-2 number, since 2×1202231300992272 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120223130099297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60111565049613 + 60111565049614.
It is an arithmetic number, because the mean of its divisors is an integer number (60111565049614).
Almost surely, 2120223130099227 is an apocalyptic number.
120223130099227 is a deficient number, since it is larger than the sum of its proper divisors (1).
120223130099227 is an equidigital number, since it uses as much as digits as its factorization.
120223130099227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 163296, while the sum is 43.
The spelling of 120223130099227 in words is "one hundred twenty trillion, two hundred twenty-three billion, one hundred thirty million, ninety-nine thousand, two hundred twenty-seven".
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