Base | Representation |
---|---|
bin | 11011010101011110100000… |
… | …111101101001110111101111 |
3 | 120202200012220122102111112222 |
4 | 123111132200331221313233 |
5 | 111224213432301133213 |
6 | 1103405424333145555 |
7 | 34215556144553516 |
oct | 3325364075516757 |
9 | 522605818374488 |
10 | 120223130099183 |
11 | 35341385804261 |
12 | 1159806b02b2bb |
13 | 5210cb9759967 |
14 | 2198b8b02767d |
15 | dd742d537808 |
hex | 6d57a0f69def |
120223130099183 has 2 divisors, whose sum is σ = 120223130099184. Its totient is φ = 120223130099182.
The previous prime is 120223130099087. The next prime is 120223130099227. The reversal of 120223130099183 is 381990031322021.
It is an a-pointer prime, because the next prime (120223130099227) can be obtained adding 120223130099183 to its sum of digits (44).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120223130099183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120223130099383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60111565049591 + 60111565049592.
It is an arithmetic number, because the mean of its divisors is an integer number (60111565049592).
Almost surely, 2120223130099183 is an apocalyptic number.
120223130099183 is a deficient number, since it is larger than the sum of its proper divisors (1).
120223130099183 is an equidigital number, since it uses as much as digits as its factorization.
120223130099183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 139968, while the sum is 44.
The spelling of 120223130099183 in words is "one hundred twenty trillion, two hundred twenty-three billion, one hundred thirty million, ninety-nine thousand, one hundred eighty-three".
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