Base | Representation |
---|---|
bin | 11011010101011110110001… |
… | …001000100101111100010101 |
3 | 120202200020121112221010020101 |
4 | 123111132301020211330111 |
5 | 111224220011224332013 |
6 | 1103405511304134101 |
7 | 34215565650602311 |
oct | 3325366110457425 |
9 | 522606545833211 |
10 | 120223401402133 |
11 | 35341504968177 |
12 | 11598125a67331 |
13 | 5211030a1a853 |
14 | 2198bb508ab41 |
15 | dd74472788dd |
hex | 6d57b1225f15 |
120223401402133 has 2 divisors, whose sum is σ = 120223401402134. Its totient is φ = 120223401402132.
The previous prime is 120223401402127. The next prime is 120223401402157. The reversal of 120223401402133 is 331204104322021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114393335212324 + 5830066189809 = 10695482^2 + 2414553^2 .
It is a cyclic number.
It is not a de Polignac number, because 120223401402133 - 213 = 120223401393941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120223401402163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60111700701066 + 60111700701067.
It is an arithmetic number, because the mean of its divisors is an integer number (60111700701067).
Almost surely, 2120223401402133 is an apocalyptic number.
It is an amenable number.
120223401402133 is a deficient number, since it is larger than the sum of its proper divisors (1).
120223401402133 is an equidigital number, since it uses as much as digits as its factorization.
120223401402133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 120223401402133 its reverse (331204104322021), we get a palindrome (451427505724154).
The spelling of 120223401402133 in words is "one hundred twenty trillion, two hundred twenty-three billion, four hundred one million, four hundred two thousand, one hundred thirty-three".
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