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12022992912613 is a prime number
BaseRepresentation
bin1010111011110101001000…
…1110001100000011100101
31120120101110001022002022111
42232331102032030003211
53033441042141200423
641323141532001021
72350426654363114
oct256752216140345
946511401262274
1012022992912613
113915a17073421
121422178000171
136929c0169b17
142d7cb7583c7b
1515cb2b7d060d
hexaef5238c0e5

12022992912613 has 2 divisors, whose sum is σ = 12022992912614. Its totient is φ = 12022992912612.

The previous prime is 12022992912599. The next prime is 12022992912629. The reversal of 12022992912613 is 31621929922021.

12022992912613 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11887062808644 + 135930103969 = 3447762^2 + 368687^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12022992912613 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12022992912713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011496456306 + 6011496456307.

It is an arithmetic number, because the mean of its divisors is an integer number (6011496456307).

Almost surely, 212022992912613 is an apocalyptic number.

It is an amenable number.

12022992912613 is a deficient number, since it is larger than the sum of its proper divisors (1).

12022992912613 is an equidigital number, since it uses as much as digits as its factorization.

12022992912613 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 419904, while the sum is 49.

The spelling of 12022992912613 in words is "twelve trillion, twenty-two billion, nine hundred ninety-two million, nine hundred twelve thousand, six hundred thirteen".