Base | Representation |
---|---|
bin | 11011010101100101000010… |
… | …110011000110110001011011 |
3 | 120202200220000012012001010211 |
4 | 123111211002303012301123 |
5 | 111224322311343212032 |
6 | 1103412544112151551 |
7 | 34216224645534253 |
oct | 3325450263066133 |
9 | 522626005161124 |
10 | 120230140210267 |
11 | 3534435283449a |
12 | 115994a68385b7 |
13 | 5211865b92b99 |
14 | 2199254056963 |
15 | dd76ddb9c747 |
hex | 6d5942cc6c5b |
120230140210267 has 2 divisors, whose sum is σ = 120230140210268. Its totient is φ = 120230140210266.
The previous prime is 120230140210261. The next prime is 120230140210339. The reversal of 120230140210267 is 762012041032021.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120230140210267 - 23 = 120230140210259 is a prime.
It is a super-3 number, since 3×1202301402102673 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (120230140210261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60115070105133 + 60115070105134.
It is an arithmetic number, because the mean of its divisors is an integer number (60115070105134).
Almost surely, 2120230140210267 is an apocalyptic number.
120230140210267 is a deficient number, since it is larger than the sum of its proper divisors (1).
120230140210267 is an equidigital number, since it uses as much as digits as its factorization.
120230140210267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 120230140210267 its reverse (762012041032021), we get a palindrome (882242181242288).
The spelling of 120230140210267 in words is "one hundred twenty trillion, two hundred thirty billion, one hundred forty million, two hundred ten thousand, two hundred sixty-seven".
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