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12023101013117 is a prime number
BaseRepresentation
bin1010111011110101100010…
…1010100011110001111101
31120120101201120201011022212
42232331120222203301331
53033441302324404432
641323200352550205
72350432436253665
oct256753052436175
946511646634285
1012023101013117
113915a72097987
1214221a8252365
13692a0968870c
142d7cc7a831a5
1515cb360352b2
hexaef58aa3c7d

12023101013117 has 2 divisors, whose sum is σ = 12023101013118. Its totient is φ = 12023101013116.

The previous prime is 12023101013111. The next prime is 12023101013141. The reversal of 12023101013117 is 71131010132021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9938502146521 + 2084598866596 = 3152539^2 + 1443814^2 .

It is a cyclic number.

It is not a de Polignac number, because 12023101013117 - 24 = 12023101013101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12023101013092 and 12023101013101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12023101013111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011550506558 + 6011550506559.

It is an arithmetic number, because the mean of its divisors is an integer number (6011550506559).

Almost surely, 212023101013117 is an apocalyptic number.

It is an amenable number.

12023101013117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12023101013117 is an equidigital number, since it uses as much as digits as its factorization.

12023101013117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 12023101013117 its reverse (71131010132021), we get a palindrome (83154111145138).

The spelling of 12023101013117 in words is "twelve trillion, twenty-three billion, one hundred one million, thirteen thousand, one hundred seventeen".