Base | Representation |
---|---|
bin | 11011010101100110111000… |
… | …010100111011011100010011 |
3 | 120202201002002121110220021121 |
4 | 123111212320110323130103 |
5 | 111224340331133323102 |
6 | 1103413511510503111 |
7 | 34216324550550442 |
oct | 3325467024733423 |
9 | 522632077426247 |
10 | 120232112011027 |
11 | 353451748705a5 |
12 | 11599957064a97 |
13 | 5211abb545ab3 |
14 | 219939dc90d59 |
15 | dd77a6d3eb37 |
hex | 6d59b853b713 |
120232112011027 has 2 divisors, whose sum is σ = 120232112011028. Its totient is φ = 120232112011026.
The previous prime is 120232112010937. The next prime is 120232112011049. The reversal of 120232112011027 is 720110211232021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120232112011027 - 211 = 120232112008979 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120232112010992 and 120232112011010.
It is not a weakly prime, because it can be changed into another prime (120232112011087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60116056005513 + 60116056005514.
It is an arithmetic number, because the mean of its divisors is an integer number (60116056005514).
Almost surely, 2120232112011027 is an apocalyptic number.
120232112011027 is a deficient number, since it is larger than the sum of its proper divisors (1).
120232112011027 is an equidigital number, since it uses as much as digits as its factorization.
120232112011027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 120232112011027 its reverse (720110211232021), we get a palindrome (840342323243048).
The spelling of 120232112011027 in words is "one hundred twenty trillion, two hundred thirty-two billion, one hundred twelve million, eleven thousand, twenty-seven".
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