120234130011251 has 2 divisors, whose sum is σ = 120234130011252. Its totient is φ = 120234130011250.

The previous prime is 120234130011133. The next prime is 120234130011253. The reversal of 120234130011251 is 152110031432021.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120234130011251 is a prime.

Together with 120234130011253, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 120234130011251.

It is not a weakly prime, because it can be changed into another prime (120234130011253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60117065005625 + 60117065005626.

It is an arithmetic number, because the mean of its divisors is an integer number (60117065005626).

Almost surely, 2^{120234130011251} is an apocalyptic number.

120234130011251 is a deficient number, since it is larger than the sum of its proper divisors (1).

120234130011251 is an equidigital number, since it uses as much as digits as its factorization.

120234130011251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 120234130011251 its reverse (152110031432021), we get a palindrome (272344161443272).

The spelling of 120234130011251 in words is "one hundred twenty trillion, two hundred thirty-four billion, one hundred thirty million, eleven thousand, two hundred fifty-one".