Base | Representation |
---|---|
bin | 11011010101110001111101… |
… | …100101000111100100000011 |
3 | 120202202012210220002110121121 |
4 | 123111301331211013210003 |
5 | 111230034213343113443 |
6 | 1103423200341533111 |
7 | 34220225460054343 |
oct | 3325617545074403 |
9 | 522665726073547 |
10 | 120244011301123 |
11 | 3534a220696346 |
12 | 115a0118114197 |
13 | 5212c66878958 |
14 | 2199bac374d23 |
15 | dd7c5181a4ed |
hex | 6d5c7d947903 |
120244011301123 has 2 divisors, whose sum is σ = 120244011301124. Its totient is φ = 120244011301122.
The previous prime is 120244011301111. The next prime is 120244011301151. The reversal of 120244011301123 is 321103110442021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120244011301123 - 217 = 120244011170051 is a prime.
It is a super-2 number, since 2×1202440113011232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120244011301723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60122005650561 + 60122005650562.
It is an arithmetic number, because the mean of its divisors is an integer number (60122005650562).
Almost surely, 2120244011301123 is an apocalyptic number.
120244011301123 is a deficient number, since it is larger than the sum of its proper divisors (1).
120244011301123 is an equidigital number, since it uses as much as digits as its factorization.
120244011301123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 120244011301123 its reverse (321103110442021), we get a palindrome (441347121743144).
The spelling of 120244011301123 in words is "one hundred twenty trillion, two hundred forty-four billion, eleven million, three hundred one thousand, one hundred twenty-three".
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