Base | Representation |
---|---|
bin | 1010111011111101000000… |
… | …0001100001100000001111 |
3 | 1120120120220010210010211101 |
4 | 2232333100001201200033 |
5 | 3034004403000144212 |
6 | 41324131205403531 |
7 | 2350533163304515 |
oct | 256772001414017 |
9 | 46516803703741 |
10 | 12025103521807 |
11 | 39168aa498342 |
12 | 1422666a095a7 |
13 | 692c685008bc |
14 | 2d80379d24b5 |
15 | 15cc01c41157 |
hex | aefd006180f |
12025103521807 has 2 divisors, whose sum is σ = 12025103521808. Its totient is φ = 12025103521806.
The previous prime is 12025103521771. The next prime is 12025103521841. The reversal of 12025103521807 is 70812530152021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12025103521807 - 219 = 12025102997519 is a prime.
It is a super-3 number, since 3×120251035218073 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12025103521877) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6012551760903 + 6012551760904.
It is an arithmetic number, because the mean of its divisors is an integer number (6012551760904).
Almost surely, 212025103521807 is an apocalyptic number.
12025103521807 is a deficient number, since it is larger than the sum of its proper divisors (1).
12025103521807 is an equidigital number, since it uses as much as digits as its factorization.
12025103521807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33600, while the sum is 37.
Adding to 12025103521807 its reverse (70812530152021), we get a palindrome (82837633673828).
The spelling of 12025103521807 in words is "twelve trillion, twenty-five billion, one hundred three million, five hundred twenty-one thousand, eight hundred seven".
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