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120254004504253 is a prime number
BaseRepresentation
bin11011010101111011010001…
…001110001010011010111101
3120202210011121100001210012001
4123111323101032022122331
5111230220200123114003
61103431532122542301
734221031222640344
oct3325732116123275
9522704540053161
10120254004504253
1135353489588804
12115a2046967991
135213b9a0264b9
14219a479648b5b
15dd8138cd461d
hex6d5ed138a6bd

120254004504253 has 2 divisors, whose sum is σ = 120254004504254. Its totient is φ = 120254004504252.

The previous prime is 120254004504203. The next prime is 120254004504383. The reversal of 120254004504253 is 352405400452021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85814970467769 + 34439034036484 = 9263637^2 + 5868478^2 .

It is a cyclic number.

It is not a de Polignac number, because 120254004504253 - 233 = 120245414569661 is a prime.

It is a super-2 number, since 2×1202540045042532 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120254004504203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60127002252126 + 60127002252127.

It is an arithmetic number, because the mean of its divisors is an integer number (60127002252127).

Almost surely, 2120254004504253 is an apocalyptic number.

It is an amenable number.

120254004504253 is a deficient number, since it is larger than the sum of its proper divisors (1).

120254004504253 is an equidigital number, since it uses as much as digits as its factorization.

120254004504253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192000, while the sum is 37.

Adding to 120254004504253 its reverse (352405400452021), we get a palindrome (472659404956274).

The spelling of 120254004504253 in words is "one hundred twenty trillion, two hundred fifty-four billion, four million, five hundred four thousand, two hundred fifty-three".